sorry about all the typos. Im a fast typer and don't always catch them. here's the question again
The system 3x-y+4=0 and x^2-8y-1=0 will have
A. 0 real solutions
B. 1 real solutions
C. 2 real solutions
D. an infinite number of real solutions
y = 3 x + 4
8 y = x^2 - 1
===========
8(3 x + 4) = x^2 - 1
24 x + 32 = x^2 - 1
x^2 - 24 x - 31 = 0
a = 1, b = -24 , c = -31
b^2- 4 a c = 576 -4*1*-31 = 700 positive so real roots
x = [ 24 +/- 10 sqrt 7 ] / 2