In right triangle JKL, ∠L is a right angle, m∠J=62∘, and JK=17.
sin62∘≈0.88
cos62∘≈0.47
tan62∘≈1.88
Triangle J K L as described in the text.
What is the measurement of JL?
If necessary, round your answer to one decimal place, like this: 42.5
I HAVE NO IDEA! I've tried different methods and all, and it's just not making sense
JL/17 = cos62°
better review your basic trig functions, yeah?
To find the measurement of JL, we can use the trigonometric ratios involving angle J.
We are given the length of JK and the measure of angle J. Since ∠L is a right angle, we have a right triangle JKL.
We know the value of sin62°, cos62°, and tan62°, which are provided as approximations in the question.
First, let's find the length of KL using cosine (cos) ratio:
cos62° = KL / JK
Rearranging the equation, we have:
KL = cos62° * JK
Substituting the values:
KL = 0.47 * 17
KL ≈ 7.99
Now, we can find the length of JL using the Pythagorean theorem:
JL² = JK² + KL²
Substituting the values:
JL² = 17² + 7.99²
JL ≈ √(289 + 63.84)
JL ≈ √352.84
JL ≈ 18.8
Therefore, the measurement of JL is approximately 18.8.