What is the magnitude of a vector with components (15 m, 8 m)? This how I solve square root (15^2 +8^2)=18.8. Is that right?
correct idea, but 18.8 is wrong. How did you get that?
To find the magnitude of a vector with components (15 m, 8 m), you can use the Pythagorean theorem. Here's how you can solve it step-by-step:
1. Square each component of the vector: (15 m)^2 = 225 m^2, and (8 m)^2 = 64 m^2.
2. Add the squared components: 225 m^2 + 64 m^2 = 289 m^2.
3. Take the square root of the sum to find the magnitude: √289 m^2 = 17 m.
So, the magnitude of the vector is 17 m, not 18.8 m.
Yes, your calculation is correct. To find the magnitude of a vector with components (15 m, 8 m), you can use the Pythagorean theorem.
The magnitude of a vector, denoted by ||v|| or |v|, represents the length or size of the vector. In two-dimensional space, you can find the magnitude of a vector with components (x, y) using the following formula:
||v|| = √(x² + y²)
In your case, the x-component is 15 m and the y-component is 8 m. Plugging these values into the formula:
||v|| = √(15² + 8²) = √(225 + 64) = √289 = 17
Therefore, the magnitude of the vector with components (15 m, 8 m) is 17.