Points (-2,1) and (3,y) have a slope of -3. Find the y coordinate of the point.
if the slope is -3, then as x grows by 5, y drops by 15
so y = 1-15 = -14
Ah, slopey dilemmas! Don't worry, I'm here to help. So, to find the y-coordinate, we can use the slope formula:
slope = (y2 - y1) / (x2 - x1)
Given that the slope is -3, and one point is (-2,1), we can plug in the values like so:
-3 = (y - 1) / (3 - (-2))
That gives us:
-3 = (y - 1) / 5
Now, we can cross multiply and solve for y:
-15 = y - 1
Adding 1 to both sides, we get:
y = -14
So, the y-coordinate for the second point would be -14. Voila!
To find the y-coordinate of the point (3, y), given that the slope between (-2, 1) and (3, y) is -3, we can use the slope formula:
m = (change in y) / (change in x)
First, let's calculate the change in x:
change in x = x2 - x1
= 3 - (-2)
= 3 + 2
= 5
Since the slope is given as -3, we can now plug the values into the slope formula and solve for the change in y:
-3 = (change in y) / (change in x)
-3 = (y - 1) / 5
Cross-multiplying gives us:
-3 * 5 = y - 1
-15 = y - 1
Now, let's isolate y by adding 1 to both sides of the equation:
-15 + 1 = y - 1 + 1
-14 = y
Therefore, the y-coordinate of the point (3, y) is -14.
To find the y-coordinate of the point (3, y), we can use the slope formula. The slope formula is:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) and (x2, y2) are the coordinates of two points on a line, and m is the slope of the line.
Given that the points (-2,1) and (3, y) have a slope of -3, we can substitute the coordinates into the slope formula. Let's denote (-2, 1) as (x1, y1) and (3, y) as (x2, y2):
-3 = (y2 - y1) / (x2 - x1)
Substituting the coordinates, we have:
-3 = (y - 1) / (3 - (-2))
Simplifying the equation, we get:
-3 = (y - 1) / 5
To solve for y, we can cross-multiply:
-15 = y - 1
Adding 1 to both sides, we have:
-14 = y
Therefore, the y-coordinate of the point (3, y) is -14.