how do you solve this equation using the substitution method:
2x−3y=−1
y=x−1
substituting y = x-1, the first equation becomes
2x - 3(x-1) = -1
solve for x, and then you can get y
To solve the equation using the substitution method, we need to substitute the value of y from the second equation into the first equation.
Given:
2x - 3y = -1 ...(Equation 1)
y = x - 1 .......(Equation 2)
We substitute Equation 2 into Equation 1. Rewrite Equation 1 using Equation 2:
2x - 3(x - 1) = -1
Now, we simplify and solve for x:
2x - 3x + 3 = -1
-1x + 3 = -1
-1x = -4
Dividing both sides by -1:
x = 4
Now that we have the value of x, we can substitute it back into Equation 2 to find the value of y:
y = 4 - 1
y = 3
Therefore, the solution to the given system of equations is x = 4 and y = 3.