If the range of y= 1/f(x) is {y|y</= or y>0,yER}, then the range of y= f(x)
may be?
Looks to me like the range of 1/f(x) is all real numbers if y≤0 or y>0
That means that f(x) ≠ 0, since 1/0 is undefined
may be?
That means that f(x) ≠ 0, since 1/0 is undefined