what is the average gravitational force of attraction between the earth and the sun? the earth averages a distance of about 150 million km(aka 1.5x10^8 km). the earth has a mass of 5.97x10^24 kg, and the sun has a mass of about 2x10^30 kg.
Correct me if I'm wrong
F=GmM/r^2
F= 6.67x10^-11(2×10^30)(5.97×10^24)/(150000000000)^2
F= 3.54x10^22 N
150 * 10^6 km = 150 * 10^6 * 10^3 meters/km = 1.50 * 10^11 meters
6.67 *10^-11 (2*10^30)(5.97*10^24) / (2.25*10^22)
= [6.67*2*5.97/2.25] * 10^(-11+30+24 -22)
= 35.4 * 10^21 = 3.54 * 10^22 agree
Your calculations are almost correct! To find the average gravitational force of attraction between the Earth and the Sun, we can use Newton's Law of Universal Gravitation:
F = G * (m1 * m2) / r^2
where:
F is the gravitational force between the Earth and the Sun,
G is the gravitational constant (approximately 6.67 × 10^-11 N m^2 / kg^2),
m1 is the mass of the Earth (5.97 × 10^24 kg),
m2 is the mass of the Sun (2 × 10^30 kg), and
r is the average distance between the Earth and the Sun (150 million km or 1.5 × 10^8 km).
We need to convert the distance between the Earth and the Sun from kilometers (km) to meters (m) since the gravitational constant is in terms of meters:
1 km = 1,000 m
Converting 1.5 × 10^8 km to meters:
1.5 × 10^8 km = 1.5 × 10^8 km * 1,000 m/km = 1.5 × 10^11 m
Now let's substitute the values into the equation:
F = (6.67 × 10^-11 N m^2 / kg^2) * (2 × 10^30 kg) * (5.97 × 10^24 kg) / (1.5 × 10^11 m)^2
Calculating this expression:
F ≈ 3.52 × 10^22 N
Therefore, the average gravitational force of attraction between the Earth and the Sun is approximately 3.52 × 10^22 Newtons.