if log2 =0.301 than log20 =?

Log 20 = log 2 x log 10

0.3010 +1
=1.3010

log20 = log10 + log2 = 1.301

To find the value of log20, we can use the logarithmic properties. Specifically, we can use the following rule:

log(ab) = log(a) + log(b)

Given log2 = 0.301, we can plug this value into the equation above:

log20 = log(2 * 10)

Using the logarithmic property, we can rewrite the equation as:

log20 = log(2) + log(10)

Now, we know that log2 = 0.301, but what is log10? Since 10 = 2^1 * 5^1, we can further simplify the equation using the logarithmic properties:

log20 = log(2) + (log(2^1) + log(5^1))

log20 = log(2) + (1 * log(2) + 1 * log(5))

Now we substitute the known value:

log20 = 0.301 + (1 * 0.301 + 1 * log(5))

We still need the value of log(5), which we can look up using logarithm tables or use a calculator. The exact value for log(5) is approximately 0.699. Substituting this value back into the equation:

log20 = 0.301 + (1 * 0.301 + 1 * 0.699)

log20 = 0.301 + (0.301 + 0.699)

Adding all the terms:

log20 = 0.301 + 0.301 + 0.699

log20 = 1.301

Therefore, log20 is approximately equal to 1.301.