How much thermal energy must be removed from a 0.34-kg chunk of ice to lower its temperature by 6.0 ∘C?
mass * specific heat * Δt = ? J
To calculate the amount of thermal energy that needs to be removed, we can use the formula:
Q = m * c * ΔT
Where:
Q = heat energy in joules
m = mass of the object in kg
c = specific heat capacity of the material in J/kg⋅°C
ΔT = change in temperature in °C
In this case, we are dealing with a chunk of ice, so we need to use the specific heat capacity of ice, which is approximately 2090 J/kg⋅°C.
Given:
m = 0.34 kg (mass of the ice)
c = 2090 J/kg⋅°C (specific heat capacity of ice)
ΔT = -6.0 °C (change in temperature, negative sign indicates a decrease in temperature)
Plugging the values into the formula:
Q = 0.34 kg * 2090 J/kg⋅°C * (-6.0 °C)
Q = - 2691.24 J
Therefore, approximately 2691.24 joules of thermal energy must be removed from the chunk of ice to lower its temperature by 6.0 °C.