Question

An arrow is fired at 55 degrees with a velocity of 20 m/s. How long is the arrow in the air?

Answer 1

Yo = 20*sin55 = 16.4 m/s.

Y = Yo+g*Tr = 0
16.4-9.8Tr = 0
16.4-9.8Tr = 0
Tr = 1.67 s = Rise time.
Tf = Tr = 1.67 s = Fall time
Tr+Tf = 1.67+1.67 = 3.34 s = Time in air.