How many grams of solute are needed to prepare 1.00 L of 0.200 M NaCl?
well, you need 0.2 moles.
How many grams of NaCl is that?
angel
To determine the number of grams of solute needed to prepare a certain molarity of a solution, you need to use the formula:
grams of solute = molarity × volume (in liters) × molar mass of solute
In this case, you want to prepare 1.00 L of a 0.200 M NaCl solution.
Step 1: Find the molar mass of NaCl
The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl). The atomic mass of sodium is 22.99 g/mol and the atomic mass of chlorine is 35.45 g/mol.
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Step 2: Use the formula to find grams of solute
Now you can plug the values into the formula:
grams of solute = 0.200 M × 1.00 L × 58.44 g/mol = 11.688 grams of NaCl
Therefore, you will need 11.688 grams of NaCl to prepare 1.00 L of a 0.200 M NaCl solution.