Cliff divers at Acapulco jump into the sea from a cliff 37.1 m high. At the level of the distance of 7.74m. The acceleration of gravity is 9.8 m/s
To calculate the time it takes for the cliff divers to reach the water, we can use the kinematic equation:
h = (1/2)gt^2
Where:
h = height of the cliff (37.1 m)
g = acceleration due to gravity (9.8 m/s^2)
t = time taken to fall
First, let's find the time it takes for the divers to fall from the top of the cliff (37.1 m). In this case, the distance traveled is the full height of the cliff. Rearranging the equation, we get:
t = sqrt((2h) / g)
Substituting the given values:
t = sqrt((2 * 37.1 m) / 9.8 m/s^2)
t = sqrt(74.2 / 9.8)
t = sqrt(7.57)
t ≈ 2.75 seconds
Next, to find the time it takes for the divers to reach the water from a distance of 7.74 m, we can use the same equation and adjust the height:
t = sqrt((2 * (h - distance)) / g)
Substituting the given values:
t = sqrt((2 * (37.1 m - 7.74 m)) / 9.8 m/s^2)
t = sqrt((2 * 29.36 m) / 9.8 m/s^2)
t = sqrt(5.97)
t ≈ 2.44 seconds
Therefore, the time it takes for the cliff divers to reach the water from a distance of 7.74 m is approximately 2.44 seconds.