. The Great Pyramid of Cheops has a square base of 230 meters on each side, and a height of 147 meters. Find the exposed surface area in square meters
Oh, you caught me off-guard with a math question! Well, first we need to calculate the area of each face of the pyramid. Since it has a square base, each face is a square, and the area formula for a square is just side times side.
So, the area of each face is 230m * 230m = 52,900 square meters. Since there are four faces on a pyramid, we multiply this area by 4 to get the total surface area of the four sides.
However, we also need to consider the exposed top of the pyramid. Since it is also a square, its area is 230m * 230m = 52,900 square meters.
Adding up the surface area of the four sides and the top, we get a total exposed surface area of 52,900 square meters * 4 + 52,900 square meters = 211,600 square meters.
Voila! The exposed surface area of the Great Pyramid of Cheops is approximately 211,600 square meters. Now, let's crack some more jokes, shall we?
To find the exposed surface area of the Great Pyramid of Cheops, we need to calculate the area of each face and add them up.
The Great Pyramid of Cheops has four identical triangular faces and one square base.
First, let's calculate the area of the base:
The base of the pyramid is a square with sides measuring 230 meters.
Therefore, the area of the base = side length squared
Area of the base = 230 meters * 230 meters = 52,900 square meters
Next, let's calculate the area of each triangular face:
The height of the pyramid is 147 meters, and the base of each triangular face is the same as the side length of the base, which is 230 meters.
The formula to calculate the area of a triangle is 1/2 * base * height.
Area of each triangular face = 1/2 * 230 meters * 147 meters = 16,955 square meters
Since there are four identical triangular faces, the total area of all four triangular faces = 4 * 16,955 square meters = 67,820 square meters
Finally, to find the total exposed surface area of the Great Pyramid of Cheops, we add the areas of the base and the triangular faces:
Total exposed surface area = Area of base + Area of all four triangular faces
Total exposed surface area = 52,900 square meters + 67,820 square meters
Total exposed surface area = 120,720 square meters
Therefore, the exposed surface area of the Great Pyramid of Cheops is 120,720 square meters.
To find the exposed surface area of the Great Pyramid of Cheops, we need to calculate the area of each face and then sum them up.
The pyramid has a square base, so it has four identical triangular faces and one square face.
First, let's calculate the area of the square face:
Area of a square = side * side
Area of the square face = 230 meters * 230 meters = 52,900 square meters
Next, let's calculate the area of the triangular faces:
Area of a triangle = (base * height) / 2
The base of each triangular face is the same as the side length of the square base, which is 230 meters. The height of each triangular face is the height of the pyramid, which is 147 meters.
Area of each triangular face = (230 meters * 147 meters) / 2 = 16,965 square meters
Since there are four identical triangular faces, the total area of the triangular faces is:
Total area of the triangular faces = 4 * 16,965 square meters = 67,860 square meters
Finally, we can calculate the total exposed surface area by summing up the area of the square face and the area of the triangular faces:
Total exposed surface area = Area of the square face + Total area of the triangular faces
Total exposed surface area = 52,900 square meters + 67,860 square meters = 120,760 square meters
So, the exposed surface area of the Great Pyramid of Cheops is 120,760 square meters.
the height of the four triangular faces is ... √(115^2 + 147^2)
exposed surface area = 4 * (1/2 * 230 * height)