If “n” is an even integer what are the next three consecutive integers
if n is any integer, even or not, the next three are
n+1, n+2, n+3
To find the next three consecutive integers for an even integer "n", we add 1, 2, and 3 to "n". This will give us the next three consecutive integers.
So, the next three consecutive integers for "n" will be n+1, n+2, and n+3.
For example, if "n" is 6, the next three consecutive integers will be 7, 8, and 9.
Therefore, the next three consecutive integers for an even integer "n" would be n+1, n+2, and n+3.
If "n" is an even integer, it means that "n" can be expressed as "2k", where "k" is some integer. To find the next three consecutive integers, we can simply add 1, 2, and 3 to "n".
So, the next three consecutive integers after "n" would be:
- "n + 1"
- "n + 2"
- "n + 3"
Substituting "n" with "2k", we can express the three consecutive integers as:
- "2k + 1"
- "2k + 2"
- "2k + 3"
Therefore, the next three consecutive integers, when "n" is an even integer, would be "2k + 1", "2k + 2", and "2k + 3".