The equilibrant of two forces 10N acting in the easterly direction if both forces act at a point
What is 20N West?
If they are in the same direction just add
10 cos 0 + 10 cos 0 = 10 * 1 + 10 * 1 = 20 N East
If you push West with 20 N now you have equilibrium.
To find the equilibrant of two forces, we need to consider the vector sum of the two forces. The equilibrant is the force that, when applied to the system, will balance out the combined effect of the original forces, resulting in a net force of zero.
In this case, we have two forces of 10N each acting in the easterly direction. Since the forces are acting at a point, we can represent them as vectors with the same magnitude, but opposite directions.
First, let's draw a diagram. Draw an arrow representing the first force of 10N in the easterly direction. Then, draw another arrow representing the second force of 10N in the opposite direction (the westerly direction, in this case) starting from the same point. You will notice that the two arrows cancel each other out, resulting in a net force of zero.
To find the equilibrant, draw a new arrow from the starting point to the end point of the second force. This new arrow represents the equilibrant force. Since the forces cancel each other out, the magnitude of the equilibrant is also 10N.
To summarize:
- Draw a vector representing the first force of 10N in the easterly direction.
- Draw a vector representing the second force of 10N in the opposite (westerly) direction, starting from the same point.
- Draw a vector from the starting point to the end point of the second force to represent the equilibrant force.
- The magnitude of the equilibrant force is also 10N.
So, the equilibrant of two 10N forces acting in the easterly direction, when both forces act at a point, is a 10N force in the opposite (westerly) direction.