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Physics
A car with an initial position of 75 m and an initial velocity of 5.0 m/s accelerates at an average rate of 4 m/s^2 for 2.0 s. What id the car's position after 2.0 s?
1 answer
x = Xi + Vi t + (1/2) a t^2
x = 74 + 5 * 2 + (1/2) * 4 * 2^2
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