The formula m=logI/s determines the magnitude of an earthquake, where I is the intensity of the earthquake and S is the intensity of a “standard earthquake.” How many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6? Show your work.
100
100 times, since adding 1 to the log multiples the result by 10
logb = 2+loga
logb = log100 + loga
logb = log(100a)
b = 100a
1.b Magnitude measures the energy released by the earthquake, while intensity measures the amount of damage.
2.a The National Seismic Hazard Map classifies Region A as having the “highest hazard” and Region B as having the “lowest hazard.” Based on this classification, which conclusion can you draw?
3.a The National Seismic Hazard Map classifies Region A as having the “highest hazard” and Region B as having the “lowest hazard.” Based on this classification, which conclusion can you draw? Push them up and down
4.aThe National Seismic Hazard Map classifies Region A as having the “highest hazard” and Region B as having the “lowest hazard.” Based on this classification, which conclusion can you draw? The National Seismic Hazard Map classifies Region A as having the “highest hazard” and Region B as having the “lowest hazard.” Based on this classification, which conclusion can you draw?
100% just look at the letters
Ruff!
To answer this question, we will use the formula provided: m = log(I/S), where m represents the magnitude of the earthquake, I is the intensity of the earthquake, and S is the intensity of a "standard earthquake."
Given that we want to find the difference in magnitude between an earthquake with a magnitude of 8 and an earthquake with a magnitude of 6, we can set up two equations using the given formula:
For the earthquake with magnitude 8:
8 = log(I1/S)
For the earthquake with magnitude 6:
6 = log(I2/S)
To find the difference in magnitude, we need to compare the two equations by dividing them:
8/6 = log(I1/S)/log(I2/S)
Simplifying further, we know that:
log(I1/S)/log(I2/S) = log(I1/S) - log(I2/S)
Now, we can substitute the values given in the formula:
8/6 = log(I1/S) - log(I2/S)
Since logarithms follow the property of division, the equation can be simplified to:
8/6 = log(I1/I2)
To find the base of the logarithm, we need the logarithm with the same base on both sides. The common base for logarithms is usually 10. Therefore, the equation becomes:
10^(8/6) = I1/I2
Simplifying further:
(10^(4/3)) * I2 = I1
Now, we can calculate the value of 10^(4/3) using a calculator or by converting the equation into fractional exponent notation:
10^(4/3) ≈ 5.62
Substituting this value back into the equation:
5.62 * I2 = I1
Therefore, an earthquake with a magnitude of 8 is approximately 5.62 times stronger than an earthquake with a magnitude of 6.
Therefore, an earthquake with a magnitude of 8 is approximately 5.62 times stronger than an earthquake with a magnitude of 6.