You have an idea gas in an insulated container. You compress it from a pressure of 50 × 105 Pa to 25 × 105 Pa, while keeping the volume the same at 10 m3. What is the work you did on the gas?
1. -250 J 2. -25 J 3. 0 J 4. 25 J 5. 250 J
To calculate the work done on the gas, you can use the formula:
Work = Pressure * Change in Volume
Given that the volume remains constant at 10 m^3, the change in volume (ΔV) is zero. Therefore, the work done on the gas would be:
Work = Pressure * ΔV
= (25 × 10^5 Pa - 50 × 10^5 Pa) * 0 m^3
= -25 × 10^5 Pa * 0 m^3
= 0 J
So, the answer is option 3: 0 J.