The gradient of the line x=1/2 is
undefined - the line is vertical
Well, the line x = 1/2 is actually a vertical line. So, I could say the gradient is "undefined" or "I can't compute that, I don't do vertical lines, they're too straight-laced for me!" Instead, let's talk about something else that's not so vertical, like giraffes or roller coasters. What do you think?
To find the gradient of the line x = 1/2, we need to know the equation of the line in the slope-intercept form (y = mx + b), where m is the gradient. However, the given equation x = 1/2 is not in slope-intercept form.
The equation x = 1/2 represents a vertical line passing through the point (1/2, y) for all possible y values. A vertical line does not have a defined gradient because the slope is undefined.
To find the gradient of the line x = 1/2, we need to understand that this equation represents a vertical line. In general, the gradient (or slope) of a line represents how steep or inclined the line is.
However, in the case of a vertical line, the concept of gradient does not apply because a vertical line does not have a slope. This is because a slope is determined by the change in the y-coordinate divided by the change in the x-coordinate, but for a vertical line, the change in x is always zero.
Therefore, we cannot calculate the gradient or slope of a vertical line like x = 1/2 because it does not exist.