6. Solve using the proper format. /6 (A)
a) (4) – (3) x (-2) =
b) (3) + (-5) ÷ (-1) x (-6 - 9 ) =
c) (-8)² ÷ (-4) – (12) + (-8)
To solve these expressions using the proper order of operations, also known as the PEMDAS rule (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction), we will follow these steps for each expression:
a) (4) – (3) x (-2):
1. Start by simplifying the multiplication: (-3) x (-2) = 6.
2. Now, perform the subtraction: 4 - 6 = -2.
Therefore, the solution to (4) – (3) x (-2) is -2.
b) (3) + (-5) ÷ (-1) x (-6 - 9):
1. Begin with the parentheses: (-6 - 9) = -15.
2. Next, apply the negative sign to (-15): -15 = 15 (multiplying an odd number of negatives gives a negative result).
3. Now, perform the division: (-5) ÷ (-1) = 5 (division of two negatives gives a positive result).
4. Multiply the result from step 3 by the result from step 2: 5 x 15 = 75.
5. Finally, perform the addition: 3 + 75 = 78.
Therefore, the solution to (3) + (-5) ÷ (-1) x (-6 - 9) is 78.
c) (-8)² ÷ (-4) – (12) + (-8):
1. Start by squaring -8: (-8)² = 64.
2. Perform the division: 64 ÷ (-4) = -16.
3. Now, perform the addition and subtraction in left-to-right order: -16 - 12 + (-8) = -36 + (-8) = -44.
Therefore, the solution to (-8)² ÷ (-4) – (12) + (-8) is -44.