Find the uniform acceleration that would cause a car's velocity to change from 27 m/s to 45 m/s in a 6.0-s period?
a = change in velocity / change in time
= (45-27) m/s / 6 s = 18 m/s / 6 s = 3 m/s^2
Well, let's calculate the acceleration that would cause a car's velocity to change like that.
Using the formula for uniformly accelerated motion, we have:
vf = vi + at
Where:
vf = final velocity (45 m/s)
vi = initial velocity (27 m/s)
a = acceleration (unknown)
t = time (6.0 s)
So, let's plug in the values we know:
45 m/s = 27 m/s + a * 6.0 s
Now, let's solve for a:
a = (45 m/s - 27 m/s) / 6.0 s
a = 18 m/s / 6.0 s
a = 3 m/s^2
So, the uniform acceleration that would cause a car's velocity to change from 27 m/s to 45 m/s in a 6.0-s period is approximately 3 m/s^2.
Now, if you'll excuse me, I'm going to practice my acceleration... in the world of comedy!
To find the uniform acceleration, we can use the formula:
acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 27 m/s
Final velocity (v) = 45 m/s
Time (t) = 6.0 s
Using the formula, we can substitute the known values:
acceleration = (45 m/s - 27 m/s) / 6.0 s
Simplifying the equation:
acceleration = 18 m/s / 6.0 s
acceleration = 3 m/s²
Therefore, the uniform acceleration that would cause the car's velocity to change from 27 m/s to 45 m/s in a 6.0-s period is 3 m/s².
To find the uniform acceleration, we can use the following equation:
v_f = v_i + a*t
Where:
v_f = final velocity
v_i = initial velocity
a = acceleration
t = time
Given:
v_i = 27 m/s
v_f = 45 m/s
t = 6.0 s
We can rearrange the equation to solve for acceleration (a):
a = (v_f - v_i) / t
Plugging in the given values:
a = (45 m/s - 27 m/s) / 6.0 s
Calculating the difference in velocities:
a = 18 m/s / 6.0 s
Dividing the values:
a = 3 m/s²
Therefore, the uniform acceleration that would cause the car's velocity to change from 27 m/s to 45 m/s in a 6.0-s period is 3 m/s².