Dr. Mann mixed 10.357 g of chemical A, 12.062 g of chemical B, and 7.506 g of chemical C to make 5 doses of medicine.
Too bad - he needed 10.
To find out the amount of each chemical in each dose of medicine, we can divide the total amount of each chemical by the number of doses.
1. Chemical A:
Divide the total amount of chemical A (10.357 g) by the number of doses (5):
10.357 g / 5 = 2.0714 g
So, each dose of medicine contains 2.0714 g of chemical A.
2. Chemical B:
Divide the total amount of chemical B (12.062 g) by the number of doses (5):
12.062 g / 5 = 2.4124 g
So, each dose of medicine contains 2.4124 g of chemical B.
3. Chemical C:
Divide the total amount of chemical C (7.506 g) by the number of doses (5):
7.506 g / 5 = 1.5012 g
So, each dose of medicine contains 1.5012 g of chemical C.
Therefore, each dose of medicine contains 2.0714 g of chemical A, 2.4124 g of chemical B, and 1.5012 g of chemical C.
To determine the amount of each chemical in a single dose of medicine, we need to divide the total amount of each chemical by the number of doses.
Chemical A:
10.357 g total / 5 doses = 2.0714 g per dose
Chemical B:
12.062 g total / 5 doses = 2.4124 g per dose
Chemical C:
7.506 g total / 5 doses = 1.5012 g per dose
Therefore, in a single dose of medicine, there are approximately:
- 2.0714 g of chemical A
- 2.4124 g of chemical B
- 1.5012 g of chemical C