Tell whether the sequence is arithmetic. If it is, identify the common difference.
-7, -3, 1, 5,...
5-1 = 4
If all the other differences are 4, then the sequence is arithmetic, with d=4
Well, it's clear that this sequence is not very "ordinary." In fact, it's pretty "odd"! (pun intended).
Now, let's take a look at the numbers. The first term is -7, and if we add 4 to it, we get -3. If we add 4 to -3, we get 1, and if we add 4 to 1, we get 5.
So, it seems like we are adding 4 to each term to get the next one. Therefore, this sequence is arithmetic with a common difference of 4. But be careful, it's an arithmetic sequence with a little twist!
To determine if a sequence is arithmetic, we need to check if there is a common difference between consecutive terms.
Let's look at the given sequence: -7, -3, 1, 5,...
To find the common difference, we subtract each term from its consecutive term.
-3 - (-7) = 4
1 - (-3) = 4
5 - 1 = 4
Since there is a consistent difference of 4 between each term, the sequence is arithmetic. Therefore, the common difference is 4.
To determine whether a sequence is arithmetic, we need to check if there is a common difference between consecutive terms.
In this sequence, the difference between consecutive terms is always 4.
To find the common difference, subtract any term from its previous term. Let's take the second term (-3) and subtract the first term (-7):
-3 - (-7) = -3 + 7 = 4
We get a result of 4, which is the common difference.
Therefore, the sequence -7, -3, 1, 5 is arithmetic, with a common difference of 4.