if he travels 7km 40degree west of north,then 10km east find the resultant displacement?
how far North? 7 cos 40 = 5.36
how far east? 10 - 7 sin 40 = 5.50
total distance = sqrt (5.36^2+5.50^2)
tan of angle east of north = 5.50 / 5.36
how far east? 10 - 7 sin 40 = 5.50
total distance = sqrt (5.36^2+5.50^2)
tan of angle east of north = 5.50 / 5.36