Question

Find the lowest point on an upper branch of y=2sec(2x+pi). Why is the answer (pi/2, 2)?

Answer 1

For sec(x) the upper branch has minimum at (2π.1)

so sec(2x+π) = 1 means 2x+π = 2π ==> x = π/2
2sec(2x+π) has the minimum you want