Suppose y varies directly with x and y=-2 when x=-8. What is the value of y when x=12?
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Thank you so much!
y = kx, so y/x is constant
You want y such that
y/12 = -2/-8
What is the value of y when x = 12
To solve this problem, we need to use the concept of direct variation. In direct variation, when two variables are related directly, their ratio remains the same.
Let's suppose the direct variation equation is y = kx, where k is the constant of variation.
To find the value of k, we can use the given information that y = -2 when x = -8. Plugging these values into the equation, we have -2 = k(-8).
Solving this equation for k, we divide both sides by -8:
k = -2 / -8
k = 1/4
Now that we have the value of k, we can use it to find the value of y when x = 12.
y = kx
y = (1/4)(12)
y = 3
Therefore, when x = 12, y = 3.