A 10-volt power supply is used to power a circuit, producing a current of 2 A. If the total resistance of the circuit is doubled, how will this affect the circuit?
The current will change so that the voltage drop for a complete loop through the circuit becomes 5 V.
The voltage drops across each resistor will be unaffected because each will remain at 0 V.
The current will change so that the voltage drop for a complete loop through the circuit remains at 10 V.
The voltage drops across each resistor will all double to match the change in resistance.
The current will change so that the voltage drop for a complete loop through the circuit remains at 10 V.
yoh but wats the asnwer
@rscot you are stupid
Well, if the total resistance of the circuit is doubled, it's not going to be very resistant to change, is it? It might start going through a mid-life crisis and question its purpose in life. But don't worry, it'll figure things out eventually. In terms of the circuit, the current will actually change, so that the voltage drop for a complete loop through the circuit remains at 10 volts. Just like how you can change your hairstyle, but you'll still be you.
To understand how the total resistance affects the circuit, let's start with Ohm's Law. According to Ohm's Law, the current (I) flowing through a circuit is equal to the ratio of the voltage (V) across the circuit and the total resistance (R) of the circuit, i.e., I = V/R.
In this case, we know the voltage (V) is 10 volts and the current (I) is 2 amperes. So, using Ohm's Law, we can calculate the initial total resistance (R) using the formula R = V/I.
R = V/I
R = 10 volts / 2 amperes
R = 5 ohms
Now, let's consider the situation where the total resistance of the circuit is doubled.
If the total resistance is doubled, the new resistance (R') will be twice the initial resistance, i.e., R' = 2*R.
R' = 2*R
R' = 2 * 5 ohms
R' = 10 ohms
Now, let's calculate the current (I') flowing through the circuit with the new resistance.
I' = V/R'
I' = 10 volts / 10 ohms
I' = 1 ampere
From the calculations, we can see that when the total resistance is doubled, the current in the circuit decreases from 2 amperes to 1 ampere.
Therefore, the correct answer is: The current will change so that the voltage drop for a complete loop through the circuit remains at 10 V.
increasing the resistance lowers the current
the supply voltage doesn't change