Please Help!!
Find the zeros of the function. Enter the solutions from least to greatest.
g (x)=(x -2)(3x +3)
lesser x =
greater x =
Oh, finding zeros, huh? Sounds like a fun game of hide and seek with numbers! So, let's see what we got here. We have the function g(x) = (x - 2)(3x + 3). To find the zeros, we set g(x) equal to zero because, well, that's where the fun begins!
So, we have (x - 2)(3x + 3) = 0. Now, let's play with the parentheses. We have two potential hiding spots for zeros: x - 2 = 0 and 3x + 3 = 0.
When we solve x - 2 = 0, we find that x = 2. That's our lesser x. Now, let's move on to the next hiding spot.
After we solve 3x + 3 = 0, we find that x = -1. Ah, there you are! That's our greater x.
So, to recap:
Lesser x = 2
Greater x = -1
And there you have it, we found the zeros, or should we say, the hiding spots. Happy hunting!
To find the zeros of the function g(x) = (x - 2)(3x + 3), we set g(x) equal to zero and solve for x.
Setting g(x) = 0, we have:
(x - 2)(3x + 3) = 0
To find the zeros, we set each factor equal to zero and solve for x separately.
Setting x - 2 = 0:
x = 2
Setting 3x + 3 = 0:
3x = -3
x = -1
Therefore, the zeros of the function g(x) are x = -1 and x = 2.
From least to greatest, the solutions are:
lesser x = -1
greater x = 2
To find the zeros of the function g(x) = (x - 2)(3x + 3), we need to set g(x) equal to zero and solve for x.
1. Set g(x) = 0:
(x - 2)(3x + 3) = 0
2. Apply the zero-product property:
Either (x - 2) = 0 or (3x + 3) = 0
3. Solve for x separately:
For (x - 2) = 0:
x - 2 = 0
x = 2
For (3x + 3) = 0:
3x + 3 = 0
3x = -3
x = -3/3
x = -1
So, the zeros of the function are x = -1 and x = 2. To answer the question, the solutions from least to greatest are:
lesser x = -1
greater x = 2
oh never mind I got the answer
g (x)=(x -2)(3x +3)
lesser x = -1
greater x = 2