Code on a capacitor is (2V 114 ). What is the cabacitance and voitage rating of the capacitor?
a) 110000 microfarad and 350 V
B) 114 picofarad and 2 V • .
C) 110000 picofarad and 35O V e d.) 110000 picofarad and 2 V
To determine the capacitance and voltage rating of the capacitor with a given code, you need to understand the code format. The code typically consists of two parts: the capacitance value and the voltage rating.
In this case, the code on the capacitor is (2V 114). Let's break it down:
1. Capacitance Value: The capacitance value is given as "114". However, it is crucial to identify the units associated with the value. In this case, the code does not explicitly mention the units, but you can infer it from the context.
a) Options A and C suggest units in microfarads (μF). To convert 110,000 μF to picofarads (pF), you need to multiply by 1,000. So, option A would be 110,000 μF = 110,000,000 pF.
c) Option D suggests units in picofarads (pF).
2. Voltage Rating: The voltage rating is given as "2V". This means the capacitor can handle a voltage of 2 volts without risking damage.
Now, let's compare the options:
a) Option A: 110,000 μF and 350 V. This option indicates a capacitance value in microfarads, but the voltage rating mentioned is 350 volts, which does not match the given code. Therefore, option A is incorrect.
b) Option B: 114 pF and 2 V. This option indicates a capacitance value in picofarads and a voltage rating of 2 volts, which matches the given code exactly. Therefore, option B is correct.
c) Option C: 110,000 pF and 350 V. This option indicates a capacitance value in picofarads, but the voltage rating mentioned is 350 volts, which does not match the given code. Therefore, option C is incorrect.
d) Option D: 110,000 pF and 2 V. This option indicates a capacitance value in picofarads, but the voltage rating mentioned is 2 volts, which matches the given code exactly. Therefore, option D is correct.
So, the correct answer is option B, which is 114 picofarads and 2 volts.