What is the equation of a line, in general form, with a slope of -2 and a y-intercept of 8?
2 x + y - 8 = 0
x + 2 y - 8 = 0
2 x - y + 8 = 0
recall the slope-intercept form is y = mx+b
that is equivalent to -mx+y-b = 0
So which choice fits with your values?
Y = mx+b
Y = -2x+8
2x+y -8 = 0.
To find the equation of a line in general form, we need to use the slope-intercept form of a line, which is y = mx + b.
In this case, we have a slope of -2 and a y-intercept of 8. The slope, m, represents how steep the line is and the y-intercept, b, represents where the line intersects the y-axis.
To convert the equation into general form, we can start with the slope-intercept form y = mx + b and rearrange it by moving all terms to one side:
y = -2x + 8
Now, we want the equation in the form Ax + By + C = 0, where A, B, and C are coefficients. To get there, we can multiply the entire equation by -1 to change the sign of every term:
-y = 2x - 8
Next, we can rearrange the equation to bring it to the general form:
2x - y + 8 = 0
Therefore, the equation of the line, in general form, with a slope of -2 and a y-intercept of 8 is 2x - y + 8 = 0.