Eight times a number plus thirty-five is at most fifteen less than three times the number.

Question

Eight times a number plus thirty-five is at most fifteen less than three times the number.

Answer 1

8 x + 35 ≤ 3 x

Subtract 3 x to both sides

5 x + 35 ≤ 0

Subtract 35 to both sides

5 x ≤ - 35

Divide both sides by 5

x ≤ - 7

Answer 2

Well, well, well... looks like we've got ourselves a mathematical problem. Let's break it down, shall we?

We need to find a number, so let's call it "x". The problem says that eight times this number plus thirty-five is at most fifteen less than three times the number. In equations, it would look like this:

8x + 35 ≤ 3x - 15

Now, let's analyze this equation. The goal is to isolate the "x" variable on one side. So, let's get rid of those nasty numbers that are holding it captive.

We can start by subtracting 3x from both sides:

8x - 3x + 35 ≤ 3x - 3x - 15

Simplifying, we get:

5x + 35 ≤ -15

Uh-oh, looks like we have a problem here. It seems that no matter what value of x we use, the left side of the equation will always be greater than the right side. So, unfortunately, there is no solution to this problem! It's like trying to find a unicorn in the North Pole.

But hey, at least we had fun with the math, right? Keep those brain juices flowing!

Answer 3

To solve this problem, let's break it down step by step.

Step 1: Define the unknown. Let's represent the number we're trying to find as 'x'.

Step 2: Translate the given information into an equation. The sentence "Eight times a number plus thirty-five is at most fifteen less than three times the number" can be translated into the equation: 8x + 35 ≤ 3x - 15.

Step 3: Solve the equation. To do this, we need to isolate the variable 'x' on one side of the inequality sign. Let's start by moving the 3x term to the left side and the 35 term to the right side.

When we do that, the equation will become: 8x - 3x ≤ -15 - 35.

Simplifying both sides gives us: 5x ≤ -50.

Step 4: Solve for 'x'. Divide both sides of the inequality by 5 to isolate 'x'.

We get: x ≤ -10.

So the solution to the equation is x ≤ -10, which means that the number we are looking for is any value equal to or less than -10.