block of wood with mass 15kg is pulled 4m along a rough floor by a force of 120N. frictional force is 30N. what's the change in velocity?
net force is 120-30 = 90N
F = ma, so a = 90/15 = 6 m/s^2
v^2 = 2as = 2*6*4, so v = √48 m/s
F = ma, so a = 90/15 = 6 m/s^2
v^2 = 2as = 2*6*4, so v = √48 m/s