Jessica is 3 years younger than jenifer. Jackie is three times as old as Jessica. The differnce between jackies age and jenifers age is 11. Find the age of Jessica ,Jenifer ,and Jackie
Ja + 3 = Jr
Je = 3 Ja
Je = Jr + 11
substituting ... 3 Ja = Ja + 3 + 11
solve for Ja , then substitute back to find Je and Jr
Jenifer = X.
Jessica = x-3.
Jackie = 3x-9.
3x-9 - x = 11
X = 10.
x-3 =
3x-9 = 3*10-9 =
To find the ages of Jessica, Jennifer, and Jackie, we need to solve the problem step by step.
Let's assume that Jennifer's age is J years. Since Jessica is 3 years younger than Jennifer, Jessica's age would be J - 3 years.
According to the problem, Jackie is three times as old as Jessica. Therefore, Jackie's age would be 3 times Jessica's age, which is 3(J - 3) years.
The problem states that the difference between Jackie's age and Jennifer's age is 11. So we can set up the equation:
Jackie's age - Jennifer's age = 11
(3(J - 3)) - J = 11
Now, let's solve the equation to find the value of J, which represents Jennifer's age:
3J - 9 - J = 11
2J - 9 = 11
2J = 20
J = 10
Now that we know Jennifer's age is 10, we can substitute this value back into the other equations to find the ages of Jessica and Jackie.
Jessica's age = Jennifer's age - 3 = 10 - 3 = 7 years
Jackie's age = 3 times Jessica's age = 3 * 7 = 21 years
So, Jessica is 7 years old, Jennifer is 10 years old, and Jackie is 21 years old.