The edge of a cube is increasing at the rate of 2 in./sec. At what rate is the volume increasing when an edge of a cube is 4 in. in length?
use the chain rule
v = s^3
dv/dt = 3s^2 ds/dt
2 = 3*16 ds/dt
ds/dt = 1/9 in/s
v = s^3
dv/dt = 3s^2 ds/dt
2 = 3*16 ds/dt
ds/dt = 1/9 in/s