Given f(x)=2ex+3, what is f−1(x)?
A. f−1(x)=ln(x−32)
B. f−1(x)=2e−x+3
C. f−1(x)=2ex+3
D. f−1(x)=−3+12lnx
Please help im really confused
switch variables to get
x = 2e^y + 3
x-3 = 2e^y
(x-3)/2 = e^y
y = ln (x/3)/2
If you meant f(x) = 2e^(x+3) then
x = 2e^(y+3)
x/2 = e^(y+3)
ln (x/2) = y+3
y = ln (x/2) - 3
Parentheses are important, and I still don't get any of your choices. But you see the steps I took. Maybe you can make things come out right.