Searches related to a block has mass of 400 kg in air. when submerged in seawater (is=1.03) it weights 2943 N. what is the specific gravity of the block?
To find the specific gravity of the block, we need to understand the concept and formula involved.
Specific gravity is the ratio of the density of a substance to the density of a reference substance. In this case, the reference substance is typically water.
The formula for calculating specific gravity is:
Specific Gravity = (Weight in air) / (Weight in air - Weight in water)
In this question, we are given the following information:
- The mass of the block in air is 400 kg.
- The weight of the block when submerged in seawater (density = 1.03 g/cm^3) is 2943 N.
Let's use this information to find the specific gravity of the block.
First, we need to convert the weight of the block in air from Newtons to kilograms. We can do this by dividing the weight in Newtons by the acceleration due to gravity (g ≈ 9.8 m/s^2).
Weight in air = 2943 N / 9.8 m/s^2 ≈ 300 kg
Now, we can substitute the values into the formula for specific gravity:
Specific Gravity = (300 kg) / (300 kg - 400 kg)
Specific Gravity = 300 kg / (-100 kg)
Specific Gravity = -3
Therefore, the specific gravity of the block is -3.