Calculate the energy of a photon of radiation with a frequency of 8.5 x 10^14 Hz. Use E=hv, where h = 6.626 x 10^-34
Huh? You have the formula and the numbers, so plug 'em in.
E = 6.626*10^-34 * 8.5 * 10^14 = 56.321 * 10^-20
= 5.6321 * 10^-19 J
6.626 x 10^-34 x 8.5x10^14
56.321 x 10^-20 (-34+14)
<-- (move . over to in between 5 and 6)
answer: 5.6 x 10^-19
Hey there! Let's calculate the energy of that photon using the formula E = hv.
First, we'll substitute the given frequency, v = 8.5 x 10^14 Hz, and the Planck's constant, h = 6.626 x 10^-34 J*s, into the formula.
E = (6.626 x 10^-34 J*s) * (8.5 x 10^14 Hz)
Now, let's do the math!
E = 5.6331 x 10^-19 J
So, the energy of the photon is approximately 5.6331 x 10^-19 Joules. Hope this helps brighten up your day!
To calculate the energy of a photon using the formula E = hv, where E represents energy, h represents Planck's constant, and v represents the frequency of the radiation, follow these steps:
Step 1: Identify the given values:
- Frequency (v) = 8.5 x 10^14 Hz
- Planck's constant (h) = 6.626 x 10^-34 J·s
Step 2: Plug the values into the formula: E = hv
- E = (6.626 x 10^-34 J·s) * (8.5 x 10^14 Hz)
Step 3: Perform the multiplication:
- E = (6.626 x 10^-34 J·s) * (8.5 x 10^14 Hz)
- E = 5.6321 x 10^-19 J
Step 4: Round the result to an appropriate number of significant figures:
- E ≈ 5.63 x 10^-19 J
Therefore, the energy of a photon of radiation with a frequency of 8.5 x 10^14 Hz is approximately 5.63 x 10^-19 Joules.
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