What volume of solution will contain 15 g of NaCl if the
solution concentration is 075 M?
15g NaCl = 0.257 moles
Really? 75 M? I'll assume 0.75M, so
0.257 moles * 1L/0.75 moles = 0.342 L or 342 mL
Well, that depends. Are you trying to make a solution or have you misplaced 15 grams of salt and are desperately searching for it? Because if it's the latter, I'm really bad at finding things. But if it's the former, let me calculate that for you! To find the volume of the solution containing 15 grams of NaCl at a concentration of 0.75 M, we can use the equation: concentration (M) = moles of solute / volume of solution (L).
First, we need to convert grams of NaCl to moles. The molar mass of NaCl is approximately 58.44 g/mol, so 15 grams of NaCl is equal to 15/58.44 = 0.257 moles of NaCl.
Now we can rearrange the equation to solve for the volume of solution: volume of solution = moles of solute / concentration. Plugging in the values, we get: volume of solution = 0.257 moles / 0.75 M = 0.343 L or 343 mL (approximately).
So, you would need approximately 343 mL of solution to contain 15 grams of NaCl at a concentration of 0.75 M. And please, let me know if you find that lost salt, I'll keep my oversized clown shoes ready for the search!
To calculate the volume of solution that will contain 15 g of NaCl, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to convert the given mass of NaCl to moles. The molar mass of NaCl is 58.44 g/mol.
Number of moles of NaCl = mass of NaCl / molar mass of NaCl
= 15 g / 58.44 g/mol
≈ 0.257 mol
Now, we can rearrange the formula to solve for the volume of solution:
Volume of solution = moles of solute / Molarity
Volume of solution = 0.257 mol / 0.75 M
≈ 0.343 L
Therefore, the volume of the solution that will contain 15 g of NaCl is approximately 0.343 liters.
To find the volume of solution that will contain 15 g of NaCl, we need to use the concentration of the solution.
The concentration of a solution is defined as the amount of solute (in moles) dissolved in a given volume of solvent (in liters). In this case, the concentration is given as 0.75 M, which means there are 0.75 moles of NaCl dissolved in 1 liter of solution.
To calculate the volume of solution needed, we can use the formula:
Volume (in liters) = Mass of solute (in grams) / Molar mass of solute (in grams/mol) / Concentration (in moles/liter)
First, we need to calculate the molar mass of NaCl. The molar mass of Na is approximately 22.99 g/mol, and the molar mass of Cl is approximately 35.45 g/mol. Adding these together gives us:
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Now we can plug the values into the formula:
Volume = 15 g / 58.44 g/mol / 0.75 mol/L
Simplifying the calculation:
Volume = 0.214 L
Therefore, the volume of solution that will contain 15 g of NaCl is approximately 0.214 liters.