If a boy spend 32% of his money and #102 left. how much he had at first
100 -32 = 68
so
0.68 m = 102
m = 102 / 0.68
He would have $236.64 at first
Did that help?
It does not help the student much just to type the answer. Moreover I do not agree with it.
To find out how much the boy had at first, we can use the information given that he spent 32% of his money and had $102 left.
Let's assume the amount he had at first is 'x'.
Since he spent 32% of his money, he would have left with 100% - 32% = 68% of his money.
We can express 68% as a decimal by dividing it by 100: 68/100 = 0.68.
We can set up an equation to represent this:
0.68 * x = 102
To solve for x, we need to isolate it on one side of the equation. We can divide both sides by 0.68:
x = 102 / 0.68
Evaluating the expression, we find:
x ≈ $150
Therefore, the boy had approximately $150 at first.