2 cells, each of End 2v and internal resistance 0.5ohms are connected in series .they are made to supply current to a combination of three resistors one of the resistance 2ohms is connected in series to a parallel combination of two other resistor each of resistance 3ohms.draw the circuit diagram and Calcucate
1. Current in the circuit
2. Potential difference across the parallel combination of the resistor.
3.losts volt of the battery
Ok thank you
2+2=4-1
=3
Quick maths
Please where is the answer ??
To solve this problem, let's break it down into a few steps.
Step 1: Drawing the Circuit Diagram
The circuit diagram consists of two cells, each with an electromotive force (EMF) of 2V and an internal resistance of 0.5Ω, connected in series. This combination supplies current to three resistors: one with a resistance of 2Ω connected in series to a parallel combination of two other resistors, each with a resistance of 3Ω.
Here's a visual representation of the circuit diagram:
```
-------------------------
| |
| Cell 1 |
| 2V, 0.5Ω |
| |
---|----------||-----------|---
| |
| |
-------------------------| |-------------------------------
| | Resistor 2 | |
| | 2Ω | |
| | | |
Cell 2 | |------------||---------| |
2V, 0.5Ω | | |
| | Resistor 3 |
| | 3Ω |
| | |
| | |
------------------------------------------------
|
------
|
Resistor 4
3Ω
```
Step 2: Calculating the Current in the Circuit
To find the current flowing in the circuit, we'll use Ohm's Law. The total resistance of the circuit can be calculated by adding the internal resistances of the two cells to the sum of the resistances of all the connected resistors.
Total resistance = (Internal resistance of Cell 1) + (Internal resistance of Cell 2) + (Resistor 2) + (Equivalent resistance of Resistor 3 and Resistor 4)
Total resistance = (0.5Ω) + (0.5Ω) + (2Ω) + (1 / ((1 / 3Ω) + (1 / 3Ω))) [Using the formula for resistors in parallel]
Total resistance = 3Ω + 2Ω + 1Ω = 6Ω
Now, we can find the current flowing in the circuit by using Ohm's Law:
Current = Total voltage / Total resistance
= (2V + 2V) / 6Ω
= 4V / 6Ω
= 2/3 A
≈ 0.67 A
Therefore, the current flowing in the circuit is approximately 0.67 Amperes.
Step 3: Calculating the Potential Difference across the Parallel Combination of Resistor 3 and Resistor 4
To calculate the potential difference across the parallel combination of resistor 3 and resistor 4, we'll use the formula for the potential difference in a parallel circuit, which states that the potential difference across each resistor in a parallel circuit is the same.
The potential difference across the parallel combination of resistor 3 and resistor 4 is equal to the potential difference across any one of them. Therefore, we only need to calculate the potential difference across either resistor 3 or resistor 4.
Potential difference across resistor 3 = Current * Resistance
= 0.67 A * 3Ω
≈ 2 V
Therefore, the potential difference across the parallel combination of resistor 3 and resistor 4 is approximately 2 Volts.
Step 4: Calculating the Lost Voltage of the Battery
The lost voltage of the battery refers to the difference between the EMF of the cell and the potential difference across the cell due to its internal resistance.
Lost voltage of the battery = EMF - (Current * Internal resistance)
= 2V - (0.67A * 0.5Ω)
= 2V - 0.335V
≈ 1.67V
Therefore, the lost voltage of the battery is approximately 1.67 Volts.
To summarize:
1. The current flowing in the circuit is approximately 0.67 Amperes.
2. The potential difference across the parallel combination of resistor 3 and resistor 4 is approximately 2 Volts.
3. The lost voltage of the battery is approximately 1.67 Volts.