An object moves 4m eastwards(E)and then 3m southwards(S).calculate the displacement from its original.
I don't know it
did you draw the diagram?
Do you recognize a 3-4-5 right triangle?
To calculate the displacement from the object's original position, we can use the Pythagorean theorem.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
In this case, the object moves 4m eastwards (along the x-axis) and then 3m southwards (along the y-axis). We can imagine this as a right-angled triangle, with the eastward movement as the horizontal side (x-axis) and the southward movement as the vertical side (y-axis).
Using the Pythagorean theorem, we can calculate the displacement from the object's original position:
Displacement = √(x^2 + y^2)
Where x is the eastward (horizontal) displacement and y is the southward (vertical) displacement.
In this case, x = 4m and y = -3m (negative sign because it's in the opposite direction of the positive y-axis). Plugging these values into the formula, we have:
Displacement = √(4^2 + (-3)^2)
= √(16 + 9)
= √25
= 5m
Therefore, the displacement from the object's original position is 5 meters.