A girl walk 12m northwards,5m eastwards and 7m southwards,Her displacement is
final displacement is 5N,5E
Now just use the Pythagorean Theorem for the distance.
Explain better
the answer is correct but I need the easy working
To find the displacement of the girl, we need to find the straight-line distance from her starting point to her ending point.
Let's visualize her movements on a coordinate grid. We'll assume her starting point is the origin (0,0).
1. The girl walks 12m northwards: This means she moves in the positive y-direction by 12 units. Her new position is (0,12).
2. She then walks 5m eastwards: This means she moves in the positive x-direction by 5 units. Her new position is (5,12).
3. Finally, she walks 7m southwards: This means she moves in the negative y-direction by 7 units. Her new position is (5,12-7) or (5,5).
Now, we have her ending position, which is (5,5). To find the displacement, we need to find the straight-line distance between her starting position (0,0) and her ending position (5,5).
We can use the Pythagorean theorem to find the distance:
Distance = sqrt((x2-x1)^2 + (y2-y1)^2)
In this case, x1 = 0, y1 = 0, x2 = 5, and y2 = 5.
Distance = sqrt((5-0)^2 + (5-0)^2)
= sqrt(25 + 25)
= sqrt(50)
≈ 7.07 meters
Therefore, the displacement of the girl is approximately 7.07 meters.