Find the coordinates of the image of Z(−7,0) after the translation (x,y)→(x+2,y−3).

bruh just add....

@gabtic so -9,-3

dude whats the answer

What are the coordinates of Rx-axis (-5,3)

To find the image of a point after a translation, we need to apply the translation rules.

Given the translation (x, y) → (x + 2, y − 3), we need to apply this rule to the coordinates of point Z.

Z(−7, 0) → Z′(x + 2, y − 3)

Substituting the values of Z into the translation rule, we get:

Z(−7, 0) → Z′(−7 + 2, 0 − 3)

Simplifying the coordinates of Z′, we find:

Z(−7, 0) → Z′(−5, −3)

Therefore, the coordinates of the image of Z after the translation are Z′(−5, −3).

Identify the coordinates of the midpoint of PQ⎯⎯⎯⎯⎯ with endpoints P(1,−1) and Q(7,−3).

so this is 8,-4

i dont think you should be in geometry...