what is the total displacement of a student who walks 3blocks east, 2 blocks north, 1 block west, and the 2 blocks south.
y = 2 -2 = 0
x = 3 -1 = 2
so
2 east
D = 3+2i-1-2i = 2+0i = 2 Blocks east.
To find the total displacement of the student, we need to calculate the net displacement in both the horizontal (east-west) and vertical (north-south) directions.
Let's break down the given movements:
1. Walking 3 blocks east: This gives us a displacement of +3 in the east-west direction.
2. Walking 2 blocks north: This gives us a displacement of +2 in the north-south direction.
3. Walking 1 block west: This gives us a displacement of -1 in the east-west direction.
4. Walking 2 blocks south: This gives us a displacement of -2 in the north-south direction.
Now, let's calculate the net displacement:
In the east-west direction:
Total displacement = (3 blocks east) + (-1 block west) = 3 - 1 = 2 blocks east.
In the north-south direction:
Total displacement = (2 blocks north) + (-2 blocks south) = 2 - 2 = 0 blocks.
Therefore, the student's total displacement is 2 blocks east and 0 blocks north.
To find the total displacement, you need to determine both the magnitude and direction of the displacement. Magnitude refers to the distance covered, while direction indicates the path taken.
In this case, the student walks 3 blocks east, 2 blocks north, 1 block west, and then 2 blocks south. Let's break down the steps:
1. Walking 3 blocks east means the student moves 3 blocks to the right.
2. Walking 2 blocks north means the student moves 2 blocks upward.
3. Walking 1 block west means the student moves 1 block to the left.
4. Walking 2 blocks south means the student moves 2 blocks downward.
Now we can calculate the displacement:
Horizontal displacement = 3 blocks east - 1 block west = 2 blocks east
Vertical displacement = 2 blocks north - 2 blocks south = 0 blocks (cancels out)
Therefore, the total displacement is 2 blocks east.