Two charges q1 and q2exert a 90 N electrostatic force onto each other when they are 1 m apart. They are moved further away to a distance of 3 m. What will the new electrostatic force be?
10 N
810 N
30 N****
270 N
Please check my answer
nope. Also an inverse-square law, so
3 times the distance means 1/9 the force.
To determine the new electrostatic force between the charges, we can use Coulomb's law, which states that the electrostatic force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Mathematically, Coulomb's law can be written as:
F = k * (|q1| * |q2|) / r^2
Where F is the electrostatic force, k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.
In this case, we know that the initial electrostatic force is 90 N when the charges are 1 m apart. Let's denote this as F1. We also want to find the new force when the charges are moved to a distance of 3 m. Let's denote this as F2.
Using Coulomb's law, we can set up the following equation:
F1 = k * (|q1| * |q2|) / (1 m)^2
To find F2, we need to rearrange the equation:
F2 = k * (|q1| * |q2|) / (3 m)^2
Since we are dealing with the same charges (q1 and q2), we can simplify the equation:
F2 = F1 * (1 m)^2 / (3 m)^2
Now, let's plug in the values:
F2 = 90 N * (1 m)^2 / (3 m)^2
Simplifying the equation further:
F2 = 90 N * 1 / 9
F2 = 10 N
Therefore, the new electrostatic force when the charges are moved to a distance of 3 m will be 10 N.