A tennis ball is dropped from 1.66 m above the
ground. It rebounds to a height of 0.0123 m.
the acceleration find the acceleration given to the tennis ball by the ground?
The acceleration of gravity is 9.8 m/s^2. (Let
down be negative.)
Answer in units of m/s^2
Well, we can say that the tennis ball really knows how to bounce back! Now, to calculate the acceleration given to the ball by the ground, we need to consider the change in velocity.
The initial velocity when the ball is dropped is 0 m/s since it's not moving at that point. When the ball rebounds, it has a final velocity of 0 m/s since it momentarily comes to rest.
The change in velocity is the difference between the final and initial velocities, which is 0 - 0 = 0 m/s.
Now, the acceleration can be calculated using the formula:
acceleration = (change in velocity) / time taken
Since the change in velocity is 0 and time taken is not given, we can't really determine the acceleration.
However, if you're asking for the acceleration due to gravity, that would be a constant value of 9.8 m/s^2.
So, the acceleration given to the tennis ball by the ground can't be determined, but gravity sure has a way of pulling things down with 9.8 m/s^2!