Potential energy of two equal negative point charge -2 micro coulomb by distance of 1m
a)2J
b)2eV
c)0.036eV
d)0.036J
What grade is this? I can't really say the answer cause I don't know it. Ask your Science teacher for extra help, like a tutor.
Recall that the force is
F = kqq/r^2
Without going into all the vector details, that means that the energy is
E = ∫ kqq/r^2 dr = -kqq/r
so plug in your numbers
To calculate the potential energy of two equal negative point charges, we can use the formula:
Potential energy (U) = (k * q^2) / r
where:
k is the electrostatic constant (9 x 10^9 Nm^2/C^2),
q is the magnitude of the charge, and
r is the distance between the charges.
Given that the charges are -2 microcoulombs (-2 * 10^(-6) C) and the distance between them is 1 meter, let's substitute these values into the formula:
U = (9 x 10^9 Nm^2/C^2) * (-2 * 10^(-6) C)^2 / 1m
U = (9 x 10^9) * 4 * 10^(-12) / 1
U = 36 x 10^(-3) J
U = 0.036 J
Therefore, the correct answer is d) 0.036 J, which represents the potential energy of the two charges.
To calculate the potential energy between two point charges, you can use the formula:
Potential energy (U) = (k * q1 * q2) / r
Where:
- k is Coulomb's constant (approximately 9 x 10^9 N m^2/C^2)
- q1 and q2 are the magnitudes of the charges
- r is the distance between the charges
In this case, the charge of each point charge is -2 microCoulomb (−2 × 10^−6 C), and the distance between them is 1 meter. Plugging these values into the formula, we get:
U = (9 × 10^9 N m^2/C^2) × (-2 × 10^(-6) C) × (-2 × 10^(-6) C) / 1 m
= 36 × 10^(-6) J
Converting the result to the given options:
a) 2 J: This is not the correct answer since the calculated potential energy is 0.036 J.
b) 2 eV: This is not the correct answer since the calculated potential energy is in joules, not electron volts (eV).
c) 0.036 eV: This is not the correct answer since the calculated potential energy is in joules, not electron volts (eV).
d) 0.036 J: This is the correct answer since the calculated potential energy is 0.036 J.