A jet makes a landing traveling due east with a speed of 120 m/s . If the jet comes to rest in 14.0 s , what is the magnitude of its average acceleration?
a = ∆v/∆t, so
-120m/s ÷ 14.0s = -8.57 m/s^2
To find the magnitude of the average acceleration, we need to determine the change in velocity and the time elapsed.
First, let's find the change in velocity. The jet initially has a speed of 120 m/s in the east direction. To come to rest, its final velocity would be 0 m/s.
Change in velocity (Δv) = Final velocity (v_f) - Initial velocity (v_i)
Δv = 0 m/s - 120 m/s
Δv = -120 m/s
Next, we divide the change in velocity by the time elapsed to find the average acceleration.
Average acceleration (a) = Δv / t
where Δv is the change in velocity and t is the time elapsed.
a = -120 m/s / 14.0 s
a ≈ -8.57 m/s²
The magnitude of the average acceleration is the absolute value of the acceleration since we are interested in the magnitude.
Magnitude of average acceleration = |a|
Magnitude of average acceleration ≈ |-8.57 m/s²|
Magnitude of average acceleration ≈ 8.57 m/s²
Therefore, the magnitude of the average acceleration is approximately 8.57 m/s².