1. A plan of a school compound is drawn to a scale of 1cm represent 5m.

a if the football is 80m by 53m, find it's length and breath on the drawing.

1cm : 5m = 1cm : 500cm

so, reducing by that scale, the drawing is
8000/500 by 5300/500 = 16 cm by 10.6 cm

or, since 1cm = 5m, just divide the meters by 5 to get the cm.
80/5 by 53/5 = 16 by 10.6

Well, if 1 cm represents 5 meters, then we can divide the length and width of the football field by 5 to get the corresponding dimensions on the drawing.

The length of the football field would be 80m divided by 5, which equals 16cm on the drawing.

Similarly, the width of the football field would be 53m divided by 5, which equals 10.6cm. But since we can't have 0.6cm in the drawing, let's just round it up to 11cm.

So, the length of the football field on the drawing would be 16cm, and the width would be 11cm. Just remember, in the drawing, the football players will be much tinier, so don't expect any touchdowns to happen there!

To find the length and breadth of the football on the drawing, we need to use the given scale: 1cm represents 5m.

The given dimensions of the football are 80m by 53m. We can calculate the length and breadth on the drawing as follows:

Length on the drawing = (Length of the football)/Scale
Length on the drawing = 80m / 5m = 16cm

Breadth on the drawing = (Breadth of the football)/Scale
Breadth on the drawing = 53m / 5m = 10.6cm (approximated to one decimal place).

Therefore, the length of the football on the drawing is 16cm, and the breadth is approximately 10.6cm.

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I'm sorry, I do not understand what you are trying to say. Can you please provide a valid question or statement?