What is the minimum, lower quartile, median, upper quartile, maximum
12,14, 12, 12, 6, 1, 18, 19, 13
To find the minimum, lower quartile, median, upper quartile, and maximum from the given data set (12, 14, 12, 12, 6, 1, 18, 19, 13), follow these steps:
1. Arrange the data in ascending order:
1, 6, 12, 12, 12, 13, 14, 18, 19
2. Find the minimum:
The minimum value is the smallest number in the data set, which is 1.
3. Find the lower quartile (Q1):
The lower quartile, or the 25th percentile, is the median of the lower half of the data set.
To find Q1, we need to find the median of the first half of the ordered data set.
The first half of the data is: 1, 6, 12
Since this set has an odd number of values, the median is the middle element, which is 6. Therefore, Q1 is 6.
4. Find the median (Q2):
The median, or the 50th percentile, is the middle value of the data set or the average of the two middle values if there is an even number of values.
The middle of the ordered data set is: 1, 6, 12, 12, 12, 13, 14, 18, 19
Since this set has an odd number of values, the median is the middle element, which is 12. Therefore, Q2 (the median) is 12.
5. Find the upper quartile (Q3):
The upper quartile, or the 75th percentile, is the median of the upper half of the data set.
To find Q3, we need to find the median of the second half of the ordered data set.
The second half of the data is: 12, 13, 14, 18, 19
Since this set has an odd number of values, the median is the middle element, which is 14. Therefore, Q3 is 14.
6. Find the maximum:
The maximum value is the largest number in the data set, which is 19.
Therefore, the minimum is 1, the lower quartile (Q1) is 6, the median (Q2) is 12, the upper quartile (Q3) is 14, and the maximum is 19.
too bad.
Sort the numbers and you have 1 6 12 12 12 13 14 18 19
Q2 is the median: 12
Q1 is the median of the lower half: 12
Q3 is the median of the upper half: 14
I assume you can figure out the minimum and maximum from the sorted list...